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[文件格式] Tutorial-on-Support-Vector-Machine
说明:Machine Learning is considered as a subfield of Artificial Intelligence and it is concerned with the development of techniques and methods which enable the computer to learn. In simple terms development of algorithms which enable the machine to learn<Faiza> 在 2025-07-24 上传 | 大小:142kb | 下载:0
[数据结构常用算法] Genetic
说明:此為求解最佳化流程之基因演算法,應用mathcad來編寫,mathcad為一簡易好上手之模擬軟體,若只是想跑小系統之初新者,建議使用-This is the process of solving the genetic algorithm to optimize the application mathcad to write, mathcad for a simple simulation software to use it well, if only wanted to run at th<張騰文> 在 2025-07-24 上传 | 大小:16kb | 下载:0
[Windows编程] OnlineSVR_C--_Code
说明:The licenses for most software designed to take away your freedom to share and change it. By contrast, the GNU General Public License is intended to guarantee your freedom to share and change free software to make sure the software is free for<Faiza> 在 2025-07-24 上传 | 大小:39kb | 下载:0
[数据结构常用算法] Quantum-Inspired-BPSO
说明:此為應用MATHCAD來編寫BPSO,為粒子群優演算法,可應用於求解最佳化過程,可跑小系統之模擬,簡單又好用-This is the application to write MATHCAD BPSO, particle swarm optimization algorithm can be applied to solve the optimization process, the simulation can run a small system, simple and easy to us<張騰文> 在 2025-07-24 上传 | 大小:18kb | 下载:0
[JSP源码/Java] Erweima
说明:android系统生成二维码程序,可以生成二维码-create the two-dimensional code base on android system<qtd> 在 2025-07-24 上传 | 大小:9kb | 下载:0
[其他小程序] OJ-Template
说明:huawei oj题目 在字符串中找出连续最长的数字串 可以参考-huawei oj : to find the longest consecutive string of digits in the string<tsoc> 在 2025-07-24 上传 | 大小:3.77mb | 下载:0
[单片机(51,AVR,MSP430等)] lion_controller
说明:电池保护板软件,带均衡功能,软件控制均衡点可随意调整,灵活,可靠。-battery protecting board with the average charging function.<yaoyangui> 在 2025-07-24 上传 | 大小:19kb | 下载:0
[软件工程] SoftwareDesign
说明:本资料为大一软件设计的教学课件,讲解内容清晰有条理,简明易懂,适合C++编程初学者-This information is for freshman software design courseware, to explain the content clearly organized and easy to understand for beginners programming C++<lihongye> 在 2025-07-24 上传 | 大小:3.26mb | 下载:0