资源列表
[其他小程序] UDiskMonitor
说明:UDiskMonitor(U盘小偷,带源码,VC++可视化)-UDiskMonitor (U disk thieves, with source code, VC++ visualization)! !<AndrewCC> 在 2025-07-23 上传 | 大小:3.31mb | 下载:0
[Windows编程] daoshu
说明:对x,若有y,使得x*y mod 8 等于1,如3*3 mod 8 等于1,则称y为x的倒数,也称为乘法逆元。并非所有的x都有乘法逆元。-Of x, if y, making x* y mod 8 = 1, such as 3* 3 mod 8 = 1, then the reciprocal of y for x, also known as the multiplicative inverse. Not all the x are multiplicative inverse.<灵药> 在 2025-07-23 上传 | 大小:867kb | 下载:0
[Windows编程] totaltest
说明:测试TI DM6441平台的各硬件功能是否工作正常,可以通过命令行输入所需测试硬件内容,根据打印结果判断是否测试通过-TI DM6441 platform to test the hardware functionality is working properly, you can enter through the command-line hardware required to test the contents, according to print test results to de<李康茂> 在 2025-07-23 上传 | 大小:77kb | 下载:0
[Windows编程] ShenRuQianChuMFC
说明:深入浅出MFC(第2版)(附代码)作 者: 侯俊杰 著。本书分为四大篇。-In layman' s language and MFC (2nd edition) (with code) Author:侯俊杰book. The book is divided into four articles.<AndrewCC> 在 2025-07-23 上传 | 大小:31.36mb | 下载:0
[Windows编程] gongyueshu
说明:有键盘输入两个正整数m,n,然后输出m,n的最大公约数和最小公倍数,采用了辗转相除法得到最大公约数p,然后用m,n的乘积除以p即得最小公倍数。-There are keyboard input two positive integers m, n, then output m, n the common denominator and least common multiple using the division algorithm to be the common denominator p<灵药> 在 2025-07-23 上传 | 大小:864kb | 下载:0
[Windows编程] lisanduishu
说明:设p是素数,a是p的本原根,即a1,a2,a3,…,ap-1在mod p下产生1到p-1的所有值,所以对任何b属于{1,…,p-1},有唯一的i属于{1,…,p-1}使得ai mod p 等于p。称i为模p下以a为底b的离散对数。-P is a prime number based, a is the primitive root p, that is, a1, a2, a3, ..., ap-1 in the mod p under 1 to p-1 for all values, so fo<灵药> 在 2025-07-23 上传 | 大小:871kb | 下载:0
[Windows编程] gxFskSrv_src
说明:东进语音板卡使用范例,主要是与应用平台间的数据通信,还有与语音板卡的数据交换。同时包括语音通道的状态管理。-East to use an example of voice board, mainly between the platform and application of data communications, as well as data and voice exchange board. At the same time, including the status of the m<wanglin> 在 2025-07-23 上传 | 大小:85kb | 下载:0