[其他小程序] 123to321

说明：正数取反，C语言实现，如-123-》-321-Positive negated, C language, such as-123- " -321
<ben> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[其他小程序] fgets

说明：可掌握fgets函数的用法。可将输入的键值放入一个数组内。-Can grasp the fgets function usage. Can be input into an array of keys inside.
<赵敏捷> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[通讯编程] QPSK

说明：QPSK调制在高斯信道下的检测性能，信噪比和误比特率曲线-QPSK modulation performance under gaussian channel, on the curve of the input signal to noise ratio and bit error rate
<wangchunlan> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[通讯编程] BPSK

说明：BPSK调制在高斯信道下的性能，误比特率和信噪比的曲线-BPSK modulation performance under gaussian channel, signal to noise ratio and bit error rate curve
<wangchunlan> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[其他小程序] cjdjdjsq

说明：超级简单的易语言源码 (用了 获取焦点、返回、键代码等）-Super simple and easy language source code (using the access point, return, key code, etc.)
<刘浩哲> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[进程与线程] SharedMemory

说明：使用共享内存块的方式在进程间共享内存的例子-Using shared memory block to the shared memory between processes examples
<hahale> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[Windows编程] poj3943

说明：poj 3943 Taro attempts to tell digits to Hanako by putting straight bars on the floor. Taro wants to express each digit by making one of the forms shown in Figure 2. Since Taro may not have bars of desired lengths, Taro cannot always make forms
<li> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[Windows编程] poj3941

说明：poj 3941 Hideyuki is allowed by his father Ujisato some 1000 yen bills every month for his pocket money. In the first day of every month, the number of bills is decided as follows. Ujisato prepares n pieces of m-sided dice and declares the cutback
<li> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[Windows编程] poj3911

说明：poj 3911 Descr iption A group of N Internet Service Provider companies (ISPs) use a private communication channel that has a maximum capacity of C traffic units per second. Each company transfers T traffic units per second through the channel
<li> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[Windows编程] poj3910

说明：poj 3910 nput The input file contains several test cases. Each test case starts with an integer n (0 < n < 1000), that stands for the cardinality of S. The next line contains the numbers of S: x1, x2, ..., xn. It is known that each xi is
<li> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[其他小程序] mulVNeton

说明：matlab 的拟牛顿方法，减少计算导数带来的计算量的一种迭代方法，用来计算非线性问题。-matlab quasi-Newton methods to reduce the computational calculation of the amount of the derivative of an iterative method to calculate the nonlinear problem.
<liming> 在 2025-06-11 上传 | 大小：1kb | 下载：0

[其他小程序] dazi

说明：运行后输入屏幕上显示的字母，数对了加一分。输错退出。屏幕下方显示关卡和分数-After running the letters displayed on the input screen, plus a few of the points. The wrong exit. Bottom of the screen and score points
<netscrt> 在 2025-06-11 上传 | 大小：1kb | 下载：0