资源列表
[Linux/Unix编程] unicode
说明:linux下汉字编码说明,,linux下汉字编码说明<chenxingliang> 在 2008-10-13 上传 | 大小:495.02kb | 下载:0
[Linux/Unix编程] unicode
说明:linux下汉字编码说明,,linux下汉字编码说明-Chinese character coding under linux Descr iption,, linux under the Chinese character coding note<chenxingliang> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[系统编程] Listbox
说明:基于C++BUILDER环境,初学者很适用,代码简单易懂,对学习和借鉴有很大好处,可移植很强,我测试的版本是BCB60,Listbox自绘源代码-Based on the C++ BUILDER environment is applicable for beginners, easy-to-understand code, and has a lot to learn from the benefits of highly portable, I tested version BCB60, L<paope> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] ipchains
说明:Linux防火墙原理解析,想要进行linux下安全开发的朋友可以参考。-Linux firewall analytic principle, want to develop linux safely friends can refer to.<包永辉> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] access
说明:vlc源码,大量的access模块,如file、http、dvd、ftp、smb、tcp、dshow、mms、v4l…等等 -vlc source code, a large number of access modules, such as file, http, dvd, ftp, smb, tcp, dshow, mms, v4l ..., etc.<danway> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] fuse-2.7.4.tar
说明:FUSE文件系统开发工具,将内核层面的文件系统开发过程平移到应用层面上来。-FUSE filesystem developer,moving the filesystem developing process from kenel level to api level.<polo> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[加密解密] RSA_C_source
说明:真正完整独立运行的RSA加密解密C源代码,并有教学用的课件(PDF文件), 可以到http://zhou63.ahut.edu.cn/更新。-Truly complete stand-alone RSA C source code for encryption and decryption, as well as teaching courseware (PDF file), and you can update them on http://zhou63.ahut.edu.cn/.<zhou> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] doc
说明:unix下面对病毒,*编写的一些常用方法,本文有实际的实例程序,对于新手非常的适合-unix the following pairs of viruses, Trojans prepared by some of the commonly used methods, there are practical examples of this procedure is very suitable for the novice<李杰> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] JTAG_controller
说明:Jtag 控制器开源项目代码,基于Linux环境-Jtag Controller open source project code, based on Linux environment<redriver> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[Linux/Unix编程] rsvp-rel3.0f
说明:zRSVP c源代码实现,详细请参见doc/readme-zRSVP c source code for implementation details see doc/readme<chen> 在 2025-07-05 上传 | 大小:495kb | 下载:0
[加密解密] gcd
说明:The greatest common divisor of integers x and y is the largest integer that evenly divides both x and y. Write a recursive function gcd that returns the greatest common divisor of x and y, define recursively as follows. It y is equal to 0, then gcd(x<Jack> 在 2025-07-05 上传 | 大小:495kb | 下载:0