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TP360.2@1005
- 嵌入式应用程序开发综合实验9例:基于博创ARM300教学平台和各类手持设备 基于博创ARM300教学平台和各类手持设备-embedded application development Experiment nine cases : Based on the ARM300 Bo Chong teaching platform, and various handheld devices based on the ARM300 Bo Cho
1074,1005,1010
- acm.zju.edu.cn第1074,1005,1010题-acm.zju.edu.cn that section 1074,1005,
guisim1005
- uc/os 嵌入式系统图形界面PC机模拟仿真工具-Tool for simulating uC/OS-II Graphics User Interface (GUI) on PC Windows environment.
TP360.2@1005
- 嵌入式应用程序开发综合实验9例:基于博创ARM300教学平台和各类手持设备 基于博创ARM300教学平台和各类手持设备-embedded application development Experiment nine cases : Based on the ARM300 Bo Chong teaching platform, and various handheld devices based on the ARM300 Bo Cho
1005
- 北大ACM1005(I Think I Need a Houseboat)-North ACM1005 (I Think I Need a Houseboat)
3026226_AC_30MS_380K
- pku acm 1006的源代码，凝聚了本人的心血啊 1003--1005文件太小传不上来啊-pku acm 1006 source code, united efforts of my ah 1003- 1005 document is not up too Chuan-ah
3026731_AC_15MS_248K
- pku acm 1007的源代码，凝聚了本人的心血啊 1003--1005文件太小传不上来啊-pku acm 1007 source code, united efforts of my ah 1003- 1005 document is not up too Chuan-ah
acm
- 北大ACM题库中的部分已AC题目源码（1001，1002，1003，1004，1005，1006，1007，1008）-ACM sharPKUngfu some questions have been the subject AC source (1001,1002,1003,1004,1005,1006,1007,1008)
HDUACM1089-1096_FLYLIKEABIRD
- 杭电ACM1001～1005代码，包含基本的输入与输出格式-Hangzhou Xinhua ACM1001 ~ 1005 code contains the basic input and output format
JN-AP-1005-Wireless-UART-2v2
- JN无线传感器网络的测试代码 是uart 之间互传-Jn WSN Uart
JN-AN-1005-Wireless-UART-3v0
- jennic 公司 zigbee模块jn5148基于IEEE802.15.4的串口传输源码-jennic company zigbee module jn5148 IEEE 802.15.4-based serial transmission source
1005
- c++算法源代码，主要是POJ上面的算法，根据标号可以找到。-c++ algorithm source code, POJ above algorithm, based on the label can be found.
1003-1005
- 杭州电子科技大学ACM平台练习题1003,1004,1005解答 -Hangzhou University of Electronic Science and Technology of ACM platform exercises 1003,1004,1005 answers
woj1
- WOJ题库第1003、1005、1010、1013、1016题的c语言源代码，下载可用-WOJ questions in 1003rd, 1005, 1010, 1013, 1016 C language source code, available for download
1005
- 协成WIFI智能平台新认证模板，用于WIFI认证页面-Society as a new certification template WIFI intelligence platform for WIFI authentication page
A1005
- pat advanced level 1005. Spell It Right-Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English. Input Specification: Each input file
1005
- 北京大学online judge poj 1005
Desktop
- WOJ1002,1005,1007,1011,1028题目答案，包过-WOJ1002,1005,1007,1011,1028 topic answers bale
整合版作业（闰年+学生成绩系统）
- 1、 闰年函数：计算闰年。 2、 学生成绩系统 已在程序中保存10条学生信息，方便直接检验查询功能而无需先录入，10条记录的学号分别是1001/1002/1003/1004/1005/1006/1007/1008/1009/1010 ① 录入学生信息 ② 录入学生分数 ③ 查询信息及分数 ④ 修改信息 ⑤ 删除学生信息 （各功能均能循环进行，且实现如输入不存在的学号要求重新输入）(1 leap year function
贪心1005
- Ignatius has just come back school from the 30th ACM/ICPC. Now he has a lot of homework to do. Every teacher gives him a deadline of handing in the homework. If Ignatius hands in the homework after the deadline, the teac