我是编程小菜鸟= =，这是一个信号量互斥的经典问题，消费者生产者问题的简单实现，使用线程方式，所以在调试时须选择多线程方式。-I was programming a small rookie = = This is a classic problem of mutual exclusion semaphores, producer consumer problem s simple implementation, using threads, so when debugging multith