基于DOS的多任务系统的实现

1. 用C语言完成线程的创建和撤消，并按优先权加时间片轮转算法对多个线程进行调度；

2. 改变时间片的大小，观察结果的变化。思考：为什么时间片不能太小或太大；

3. 假设两个线程共用同一软件资源（如某一变量，或某一数据结构），请用记录型信号量来实现对它的互斥访问；

4. 假设有两个线程共享一个可存放5个整数的缓冲，一线程不停的计算1到50的平方，并将结果放入缓冲中，另一个线程不断的从缓冲中取出结果，并将他们打印出来，请用记录型信号量实现这一生产者和消费者的同步问题；

5. 实现消息缓冲通信，并于3，4中的简单通信进行比较；

6. 思考：在线程间进行消息缓冲通信时，若对消息队列的访问没有满足互斥要求，情况会怎么样？-DOS-based multi-tasking system in a. C language to complete the creation and thread lift Priority increase as time slice Web algorithm for multiple-thread scheduling; 2. change the timing of the unit size, The results change. Thoughts : Why not films too little time or too much; 3. Assuming two threads to share the same software resources (such as a variable, or a data structure), with record-volume signal to achieve its exclusive interviews. 4. Suppose two threads share a deposit of five integer buffer keep a thread of 1-50 calculating the square, and the results Add buffer, Another constant thread removed from the buffer, and print them out, Please record-volume signal achieve this producers and consumers synchronization; 5. Implementation news buffer communications, and 3, 4 simple comm