文件名称:LeiPiShu
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雷劈数的基本概念: 把 3025 从中间分开为 30 和 25 , 30+25 = 55 , 55*55 = 3025
雷劈数的规律:它们被劈成的两数之和都是 9 或 11 的倍数或其和减 1 是 9 的倍数
本例只寻找偶数位的整数是否是雷劈数.
奇数位整数的雷劈数例:100 , 10+0 = 10 , 10*10 = 100 寻找时需逐位组合判断.计算量过大
本程序在 VC++ 6.0(SP6) 环境下成功编译
*/-/* Number of mine split the basic concepts: the separation of 3025 from between 30 and 25, 30+ 25 = 55, 55* 55 = 3025 Lei split the number of law: they are the number two劈成and they are all 9 or 11 or its multiples, and by one is a multiple of 9 in this case only to find even-numbered-bit integer Is the number of mine split. odd bit integer chop mine a few examples: 100, 10+ 0 = 10, 10* 10 = 100 to find when judgment-by-bit combination. calculated in this procedure too VC++ 6.0 (SP6) environment successful compile* /
雷劈数的基本概念: 把 3025 从中间分开为 30 和 25 , 30+25 = 55 , 55*55 = 3025
雷劈数的规律:它们被劈成的两数之和都是 9 或 11 的倍数或其和减 1 是 9 的倍数
本例只寻找偶数位的整数是否是雷劈数.
奇数位整数的雷劈数例:100 , 10+0 = 10 , 10*10 = 100 寻找时需逐位组合判断.计算量过大
本程序在 VC++ 6.0(SP6) 环境下成功编译
*/-/* Number of mine split the basic concepts: the separation of 3025 from between 30 and 25, 30+ 25 = 55, 55* 55 = 3025 Lei split the number of law: they are the number two劈成and they are all 9 or 11 or its multiples, and by one is a multiple of 9 in this case only to find even-numbered-bit integer Is the number of mine split. odd bit integer chop mine a few examples: 100, 10+ 0 = 10, 10* 10 = 100 to find when judgment-by-bit combination. calculated in this procedure too VC++ 6.0 (SP6) environment successful compile* /
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LeiPiShu.rar
雷劈数.cpp
雷劈数.cpp