文件名称:Yush.java.tar

  • 所属分类:
  • CA认证
  • 资源属性:
  • [Linux] [C/C++] [源码]
  • 上传时间:
  • 2016-04-08
  • 文件大小:
  • 1kb
  • 下载次数:
  • 0次
  • 提 供 者:
  • Aman V******
  • 相关连接:
  • 下载说明:
  • 别用迅雷下载,失败请重下,重下不扣分!

介绍说明--下载内容均来自于网络,请自行研究使用

This a new algorithm in which we encrypt on the basis of position of the character.

Algorithm 1 for key generation and Algorithm 2 is for encryption

Algorithm A1

Step1: Let the key be ‘k’.

Step2: Multiply the index number +1 with its ASCII code of the character at that index-65.

Step3: Sum all the values and mod 26.

Step4: Return the key.



Algorithm A2

Step1: Take the string which you want to encrypt.

Step2: Find the number of spaces.

Step3: We add 65 to number of space.

Step4: Take a string s.

Step5: Add character representing number of spaces to that string.

Step6: Calculate the word length of all the words present in the string and 65 to it.

Step7: Now append the character that represents the word length.

Step8: Subtract the number 1 and Add the number 1 with the ASCII value of the characters at alternate position.

Step9: Add the key to each character in the string.

Step10: Subtract 65 and the value so obtained modulo 26.

Step11: Cipher text obtained.-This is a new algorithm in which we encrypt on the basis of position of the character.

Algorithm 1 for key generation and Algorithm 2 is for encryption

Algorithm A1

Step1: Let the key be ‘k’.

Step2: Multiply the index number +1 with its ASCII code of the character at that index-65.

Step3: Sum all the values and mod 26.

Step4: Return the key.



Algorithm A2

Step1: Take the string which you want to encrypt.

Step2: Find the number of spaces.

Step3: We add 65 to number of space.

Step4: Take a string s.

Step5: Add character representing number of spaces to that string.

Step6: Calculate the word length of all the words present in the string and 65 to it.

Step7: Now append the character that represents the word length.

Step8: Subtract the number 1 and Add the number 1 with the ASCII value of the characters at alternate position.

Step9: Add the key to each character in the string.

Step10: Subtract 65 and the value so obtained modulo 26.

Step11: Cipher text obtained.
(系统自动生成,下载前可以参看下载内容)

下载文件列表





57578868Yush.java.tar

相关说明

  • 本站资源为会员上传分享交流与学习,如有侵犯您的权益,请联系我们删除.
  • 本站是交换下载平台,提供交流渠道,下载内容来自于网络,除下载问题外,其它问题请自行百度更多...
  • 请直接用浏览器下载本站内容,不要使用迅雷之类的下载软件,用WinRAR最新版进行解压.
  • 如果您发现内容无法下载,请稍后再次尝试;或者到消费记录里找到下载记录反馈给我们.
  • 下载后发现下载的内容跟说明不相乎,请到消费记录里找到下载记录反馈给我们,经确认后退回积分.
  • 如下载前有疑问,可以通过点击"提供者"的名字,查看对方的联系方式,联系对方咨询.

相关评论

暂无评论内容.

发表评论

*主  题:
*内  容:
*验 证 码:

源码中国 www.ymcn.org