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3810_01_code
- ajax function use, $(document).ready(function()) $( #content h2 ).each(function(index) -ajax function use, $(document).ready(function()) $( #content h2 ).each(function(index)
kszd
- LISP快速展点程序 LISP展点程序,主要地形测量中展绘碎部点等。 展1000点:在HP(AMD Athlon64 3000+ 256MB)电胶上仅耗时0.142秒; 在金利(Geleron(R) CPU 2.40GHz 256MB)电胶上耗时0.882秒 数据文件格式为:每一点的数据(点号、X、Y、H)为一行,用逗号或空格作为分隔符,即 点号1 X1 Y1 H1 或者 点号1, X1, Y1, H1
HH2
- Algorithm (H2):the algorithme H2 is a heuristic for csp problem.
somKohonen
- Herustic H2 Algorithm:the algorithme H2 is a algorithm for csp problems.
CHANNEL
- 假设信号产生和传输信道模型为: 而抽头维纳滤波器为: 假设 的方差为0.27, 的方差为0.1,均值都为零。并且: , 并假设权向量初始值为 ,分别使用步长0.015、0.025和0.05进行 LMS算法仿真。 分析:d(n)是子系统H1受到v1(n)激励产生的信号,而H2与加性噪声构成了加性噪声传输信道。将u(n)作为维纳滤波器的输入,且滤波器的期望响应为d(n)。问题就是如何求出滤波器的权系数
html
- HTML Headings HTML headings are defined with the <h1> to <h6> tags. Example <h1>This a heading</h1> <h2>This is a heading</h2> <h3>This is a heading</h3>
33673-1081694-editeur-tag-mp3
- Editeur tag mp3--- --- --- Url : http://codes-sources.commentcamarche.net/source/33673-editeur-tag-mp3Auteur : tof2503Date : 13/08/2013 Licence : ========= Ce document intitulé « Editeur tag mp3 » issu
One-yuan-polynomial-multiplication
- 题目说明: 要求采用链表形式,求两个一元多项式的乘积:h3 = h1*h2。函数原型为:void multiplication( NODE * h1, NODE * h2, NODE * h3 )。 输入: 输入数据为两行,分别表示两个一元多项式。每个一元多项式以指数递增的顺序输入多项式各项的系数(整数)、指数(整数)。 例如:1+2x+x2表示为:<1,0>,<2,1>,
robustcontrol
- for robust control and h2 control
multiplication
- 要求采用链表形式,求两个一元多项式的乘积:h3 = h1*h2。函数原型为:void multiplication( NODE * h1, NODE * h2, NODE * h3 )。-Require the use of a linked list, find the product of two one yuan polynomial: h3 = h1* h2. Function prototype: void multiplic
abcds
- WAP to check whether a given system H1(z)and H2(z)in cascade is stable
debug-leds
- Many OMAP development platforms reuse the same debug board these platforms include H2, H3, H4, and Perseus2. -Many OMAP development platforms reuse the same debug board these platforms include H2, H3, H4, and Perseu
NEE_ospf
- 工具:Dynamips, VPCS结点:R1: 10.0.0.0/8, 90.0.0.0/8R2: 20.0.0.0/8, 90.0.0.0/8R3: 30.0.0.0/8, 90.0.0.0/8H1: 10.0.0.2H2: 20.0.0.2H3: 30.0.0.2要求:R1,R2,R3之间直接用串口(serial) 相连,采用X.25封装。分配给串口的X.25地址不作限制。目的:使得H1,H2,H3可以在IP层互通-err
debug-leds
- Many OMAP development platforms reuse the same debug board these platforms include H2, H3, H4, and Perseus2.-Many OMAP development platforms reuse the same debug board these platforms include H2, H3, H4, and Perseus2.
Dichotomy
- Dichotomy Methods Successive dichotomy uses a totally different approach to the problem of indexing. The constants A to F in the equation Q = A h2 + B k2 + C l2 + D kl + E hl + F hk are assigned minimum and m
results
- 这是一个为E马当先团队制作的物流信息查询结果的前端设计(实际系统中只要将h1,h2……中的代码换成dataset中的数据),使用的是html和css编写的。-This is a team for the production of E horse at the head of the front-end design of logistics information query results using html and css wr
Hoo
- Hoo/H2控制方法进行卫星姿态容错控制,包括卫星模型,控制器设计和参数文档-Hoo/H2 control method for satellite attitude fault-tolerant control, including satellite model, controller design and parameter document
Illustration_Norms
- or a thorough descr iption of the norms, see the Chapter 4 of Robust and Optimal Control, Zhou, Glover, Doyle 1996. Here the point is to give some lines of code illustrating what are the H2 and Hinf norms of LTI sys
rapid-calculation24CPP
- 速算24 要求: a. 一副牌54张牌,黑桃(SA,SK,SQ,SJ,S10,??,S2),红桃(HA,HK,HQ,HJ,H10,??,H2),方块(DA,DK,DQ,DJ,D10,??,D2),草花(CA,CK,CQ,CJ,C10,??,C2)以及大鬼Q1和小鬼Q2。其中,A,K,Q,J及Q1,Q2的点值分别为:1,13,12,11,1,1。其余点值就是牌值。 b. 由计算机随机出四张牌。 c. 用户输入能算
h2-2014-08-06-src
- 一种用Java实现的内存数据据库的完整源码-An in-memory data implemented in Java, according to the complete source code library