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ok_sim_simple_PI
- Effective mathematical model of IPMSM with PI controller as speed controller. Good for comparison & simulation results.
IPMSM_PI_speed
- interior permanent magnet synchronous machine speed control using pi controller
Gardner_baseband
- 对基带数字通信的位同步过程进行了仿真，采用Gardner算法，没有用插值。符号用SRRC进行脉冲成形，环路滤波器没有用PI回路，是简单的alfa，1-alfa低通滤波，NCO调整也比较简单。-Baseband digital communications for the bit synchronization process of the simulation, using Gardner algorithm, did not use
pai
- 通过多线程的编程实现圆周率简单计算方式，是多线程编程中较为简单的题目，但整体结构上比较易懂，是初学者学习多线程变成的入门代码。-Through a multi-threaded programming pi simple calculation method is relatively simple multi-threaded programming topics, but the overall structure is relat
2007298504
- 数据结构实验 之 一元多项式相加 一．实验目的 掌握链表的创建、初始化、查询以及维护的使用。 二．实验用到的原理原理 一元多项式 在计算机中，可以用一个线性表来表示: P = (p0, p1, …，pn) 一般情况下的一元稀疏多项式可写成 Pn(x) = p1xe1 + p2xe2 + ┄ + pmxem 其中：pi 是指数为ei 的项的非零系数， 0≤ e1 &
DLogicalClocks
- Distributed Logical clocks. Code will spawn n (distributed) processes Pi, 0 ≤ i < n, each one looping forever. Each loop iteration is a loop interval and its duration can be set to 1 second. In every loop interv
DME
- Java program will spawn n (distributed) processes Pi, 0 ≤ i < n, each one looping forever. Each loop iteration is a loop interval. In every loop interval Pi does the following: − It sleeps for a random amount
romberg_method_integration_order8
- NUMERICAL INTEGRATION: Implementation of the routine of order 8 and applied on the function sin(x), 0<=x<=pi Code is very understodable, and converge very fast.
cyuanzhoulv
- 圆周率PI的计算(精确到几十万位) -pi
cpi
- 计算pi值的并行程序，编程语言是c，加入mpi实现并行化-Calculated pi value of parallel programming, programming language is c, achieved by adding parallel mpi
OSIsoft-Product-Overview-4th-May-2009-R1
- OSISoft的PI实时数据库详细介绍资料，2009年最新版本-OSISoft the PI real-time database details information on the latest version of the 2009
fuzzynet
- 模糊RBF网络逼近和混合Pi-Sigma神经网络逼近-Fuzzy RBF and Pi-Sigma Approaching
Mentekaluo
- 本程序和文件主要利用蒙特拉罗的思想来完成圆周率的计算，利用事物发生的概率来逼近真实情况。-The programs and files using mainly Mengtelaluo thought to complete the calculation of pi, using the probability of things have to approximate the actual situation.
shell
- unix的shell编程，实现了哲学家就餐问题和，圆周率运算问题-unix' s shell programming, the dining philosophers problem and, pi computing problems
CPP_Make_the_to_calculate
- 利用以下公式,计算 PI 至小数点后s位 oo --- n L * PI \ (-1) 4 * L L -------- = / [ ------- ( ---------- - -------------- ) ] 4 --- 2n+1 5^(2n+1) 239^(2n+1) n=0 L : 为一大整数 10^s PI : 圆周率-Using the following
angle
- 给定2个点坐标，计算其连线与水平方向的夹角，夹角范围[0,2*pi]-failed to translate
1245
- 要求：从x(t)=sin(2*pi*5*t)+sin(2*pi*200*t)+sin(2*pi*50*t)信号中滤出频率为5Hz的信号-Requirements: from x (t) = sin (2* pi* 5* t)+ sin (2* pi* 200* t)+ sin (2* pi* 50* t) signal to filter out the signal frequency of 5Hz
small
- 计算PI的值有各种各样 ，看看这个算法是不是很简洁呢-Calculated PI values are varied, to see if this algorithm is not very simple and does
JUZHEN
- Descr iption 给定一个有N个矩阵的矩阵链A1A2A3...An，矩Ai的维数为pi-1*pi。我们都知道，使用朴素的矩阵乘法去乘两个维数分别为x,y和y,z的矩阵，所需要的乘法次数为x*y*z。矩阵链乘法问题就是如何对矩阵乘积加括号，使得它们的乘法次数达到最少。 Input 输入的第一行为一个正整数N(1<=N<=200)。表示矩阵的个数。 输入的第二行包含N+1个整数，分