搜索资源列表
LG-C280-W
- LG-C280-W手机原理图,cpu接口非常详细.-LG-C280-W mobile phone schematic, cpu interface very detailed.
w-k_Chinese_references
- 非常好的wk算法的中文参考资料，将stolt插值方面讲的很详细-Very good Chinese reference wk algorithm will Stolt interpolation side of a very detailed
CMC-CG1N0298DFSW-W-E
- LCD driver CMC-CG1N0298DFSW-W-E CSTN 128*160-LCD driver CMC-CG1N0298DFSW-WE CSTN 128* 160
CDMA_MODULATION_DEMODULATION
- 复接入，B/W双用户使用直接扩频序列 ％ >>>multiple access b/w 2 users using DS CDMA ％ >>>format is : cdmamodem(user1,user2,snr_in_dbs) ％ >>>user1 and user2 are vectors and they should be of equal length
W-cyclone-softp_1.0_src.tar
- 一个ftp搜索引擎的源代码，正在运行中的校内实用的引擎-source code of a on-line ftp search engine
Prentice.Hall.Brian.W.Kernighan.and.Dennis.M.Ritch
- [计算机科学经典著作][1].Prentice.Hall.Brian.W.Kernighan.and.Dennis.M.Ritchie.The.C.Programming.Language.2Nd.Ed.pdf-].Prentice.Hall.Brian.W.Kernighan.and.Dennis.M.Ritchie.The.C.Programming.Language.2Nd.Ed.pdf
W-CDMA
- wcda的仿真代码,涵盖了调制 信道编码等部分很有用的-the simulation of wcdma
abc
- 单循环赛中选手胜负序列求解问题 名称：单循环赛中选手胜负序列求解问题 内容：有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛，每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。 -Single round robin tournament players winning sequence to
W-CDMA
- 信道编码，交织，速率匹配，调制，扩频，信道模型，RACK接收机-W-CDMA
W-CDMA_and_cdma2000_for_3G_Mobile_Networks
- W-CDMA and cdma2000 for 3G Mobile Networks M.R. Karim and M. Sarraf McGraw-Hill New York Chicago San Francisco Lisbon London Madrid Mexico City Milan New Delhi San Juan Seoul Singapore Sydney Toronto
W-CDMA
- W-CDMA stands for Wideband Code Division Multiple Access Its an air interface standard found in 3G mobile telecommunications networks designed for “always-on” packet-based wireless service, so th
Introduction-to-Parallel-Computing-(W.-P.-Peterse
- Introduction to Parallel Computing (W. P. Petersen)
SRmatlab
- W.T.Freeman 经典 基于例子的超分辨率重构matlab源码，图片自己可加，经测试可用-WTFreeman classic example of super-resolution reconstruction based on matlab source code, images themselves can be added, the test can be used
Poznaj-C-w-24-godzin---cz-1-(do-strony-250)
- Poznaj c++ w 24 h czesc pierwsza 250 stron
12-Software-Defined-Radio---W.Tuttlebee
- Software Defined Radio - W.Tuttleb-Software Defined Radio - W.Tuttlebee
zoj2016-w-1
- zoj2016-w-1.cpp 有向欧拉通路问题，把单词首尾字母当做点，单词是他们之间的关系 1.此图连通 2.有且仅有两个点出度和入度不同，但差是1；其余点的出度和入度相等-Zoj2016-w-1. The CPP Have access to euler, put the word as a point between the letters, the word is the relationship betwe
W.-Schindler-Cryptography--B-IT--winter-2006--200
- W. Schindler Cryptography, B-IT, winter 2006 2007-W. Schindler Cryptography, B-IT, winter 2006 2007
C-W
- 旅行商算法 节约算法解决旅行商问题，可运行程序-c-w finish vrp PROBELM quick ,help c++ system
w-h
- 利用W-H规则进行网络训练时应该选取小学习率使其收敛，大的学习率会使网络发散-WH rules for network training, it should select small learning rate convergence, the learning rate will make the network divergence
w-h-02
- 用w-h规则进行网络训练的最主要的程序，很好用很简洁配注释-The main network training program wh rule, very good with the very concise with Notes